An electric dipole having each charge of magnitude 2 is placed in an electric field of intensity 8 × 10⁺⁴ N/C. If the maximum torque acting on the dipole is 4 × 10⁻³ N-m, the length of the dipole is (a) 10 mm (b) 25 mm (c) 15 mm (d) 20 mm

Answer: (b). Maximum torque ( θ = 90°): τmax = q(2l)E 2l = 4×10⁻³2×10⁻⁶× 8×10⁴ = 4×10⁻³0.16 = 0.025 m So the answer is (b) 25 mm.

An electric dipole having each charge of magnitude 2 is placed in an… | MHT CET 2025 (21 Apr, Shift 1)

Q16MHT CET 2025 · 21 APR · SHIFT 1Easy

Electric Dipole

An electric dipole having each charge of magnitude $2\mu\text{C}$ is placed in an electric field of intensity $8 \times 10^{+4}\text{ N/C}$ . If the maximum torque acting on the dipole is $4 \times 10^{-3}\text{ N-m}$ , the length of the dipole is

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Answer: (b)

Maximum torque ( $\theta = 90^\circ$ ): $\tau_{max} = q(2l)E$
$2l = \frac{4\times10^{-3}}{2\times10^{-6}\times 8\times10^{4}} = \frac{4\times10^{-3}}{0.16} = 0.025$ m
So the answer is (b) 25 mm.

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