An electric dipole is placed at an angle of 30° with an electric field of intensity 2 × 10⁵ NC⁻¹. It experiences a torque equal to 4 N m. Calculate the magnitude of charge on the dipole, if the dipole length is 2 cm. (a) 6 mC (b) 4 mC (c) 2 mC (d) 8 mC

Answer: (c). τ = q(2l)Esin θ 4 = q × 0.02 × 2×10⁵ × 1/2 = 2000 q q = 2×10⁻³ C = 2 mC So the answer is (c) 2 mC.

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Electric Dipole

An electric dipole is placed at an angle of $30^\circ$ with an electric field of intensity $2 \times 10^{5}\text{ NC}^{-1}$ . It experiences a torque equal to $4\text{ N m}$ . Calculate the magnitude of charge on the dipole, if the dipole length is $2\text{ cm}$ .

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Answer: (c)

$\tau = q(2l)E\sin\theta$
$4 = q \times 0.02 \times 2\times10^{5} \times \frac{1}{2} = 2000\,q$
$q = 2\times10^{-3}$ C $= 2$ mC
So the answer is (c) 2 mC.

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