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JEE Main 2023 (8 Apr, Shift 1) · Electric Dipole

Electric Dipole question from JEE Main 2023 (8 Apr, Shift 1)

Q43JEE Main 2023 · 8 APR · SHIFT 1Easy

Electric Dipole

An electric dipole of dipole moment 6.0×10−6 Cm6.0 \times 10^{-6}\text{ Cm} is placed in a uniform electric field of 1.5×103 NC−11.5 \times 10^{3}\text{ NC}^{-1} in such a way that dipole moment is along electric field. The work done in rotating dipole by 180∘180^\circ in this field will be ___________ mJ\text{mJ}.

Numerical answer type. Work it out, then open the answer.

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Answer: 18

  1. Rotating by 180∘180^\circ from the field direction: W=2pEW = 2pE
  2. W=2×6.0×10−6×1.5×103=18×10−3W = 2 \times 6.0\times10^{-6} \times 1.5\times10^{3} = 18\times10^{-3} J
  3. Answer: 18 mJ
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