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JEE Main 2025 (28 Jan, Shift 2) · Electric Dipole

Electric Dipole question from JEE Main 2025 (28 Jan, Shift 2)

Q22JEE Main 2025 · 28 JAN · SHIFT 2Easy

Electric Dipole

An electric dipole of dipole moment 6×10−6 Cm6 \times 10^{-6}\text{ Cm} is placed in uniform electric field of magnitude 106 V/m10^{6}\text{ V/m}. Initially, the dipole moment is parallel to electric field. The work that needs to be done on the dipole to make its dipole moment opposite to the field, will be _______ J.

Numerical answer type. Work it out, then open the answer.

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Answer: 12

  1. From parallel to antiparallel: W=pE(cos⁡0∘−cos⁡180∘)=2pEW = pE(\cos 0^\circ - \cos 180^\circ) = 2pE
  2. W=2×6×10−6×106=12W = 2 \times 6\times10^{-6} \times 10^{6} = 12 J
  3. Answer: 12 J
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