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MHT CET 2025 (19 Apr, Shift 1) · Electric Dipole

Electric Dipole question from MHT CET 2025 (19 Apr, Shift 1)

Q17MHT CET 2025 · 19 APR · SHIFT 1Easy

Electric Dipole

An electric dipole of dipole moment ' pp ' is aligned parallel to a uniform electric field ' E '. The energy required to rotate the dipole by 90∘90^\circ is [sin⁡0∘=0,sin⁡90∘=1cos⁡0∘=1,cos⁡90∘=0]\left[\begin{matrix}\sin 0^\circ = 0, & \sin 90^\circ = 1 \\ \cos 0^\circ = 1, & \cos 90^\circ = 0\end{matrix}\right]

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Answer: (a)

  1. W=pE(cos⁡θ1−cos⁡θ2)W = pE(\cos\theta_1 - \cos\theta_2)
  2. W=pE(cos⁡0∘−cos⁡90∘)=pE(1−0)=pEW = pE(\cos 0^\circ - \cos 90^\circ) = pE(1 - 0) = pE
  3. So the answer is (a) pEpE.
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