An electric dipole of length 3 cm is placed with its axis making an angle of 60° with a uniform electric field of 5 × 10⁴ N/C. It experiences a torque of 9√(3) Nm. The magnitude of charge on the dipole is (sin 60° = √(3)/2) (a) 0.6 × 10⁻² C (b) 1.2 × 10⁻² C (c) 1.8 × 10⁻² C (d) 2.4 × 10⁻² C

Answer: (b). τ = q(2l)Esin θ 9√(3) = q × 0.03 × 5×10⁴ × √(3)/2 = 750√(3) q q = 9/750 = 1.2×10⁻² C So the answer is (b) 1.2 × 10⁻² C.

An electric dipole of length 3 cm is placed with its axis making an… | MHT CET 2026 (17 Apr, Shift 1)

Q3MHT CET 2026 · 17 APR · SHIFT 1Easy

Electric Dipole

An electric dipole of length $3$ cm is placed with its axis making an angle of $60^\circ$ with a uniform electric field of $5 \times 10^{4}$ N/C. It experiences a torque of $9\sqrt{3}$ Nm. The magnitude of charge on the dipole is $\left(\sin 60^\circ = \frac{\sqrt{3}}{2}\right)$

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Answer: (b)

$\tau = q(2l)E\sin\theta$
$9\sqrt{3} = q \times 0.03 \times 5\times10^{4} \times \frac{\sqrt{3}}{2} = 750\sqrt{3}\,q$
$q = \frac{9}{750} = 1.2\times10^{-2}$ C
So the answer is (b) $1.2 \times 10^{-2}$ C.

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Electric Dipole question from MHT CET 2026 (17 Apr, Shift 1)

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