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MHT CET 2024 (3 May, Shift 1) · Electric Dipole

Electric Dipole question from MHT CET 2024 (3 May, Shift 1)

Q36MHT CET 2024 · 3 MAY · SHIFT 1Medium

Electric Dipole

An electric dipole of momentp⃗\vec{p}is lying along a uniform electric field E⃗\vec{E}. The work done in rotating the dipole through πc3\frac{\pi^c}{3} is [sin⁡30∘=cos⁡60∘=0.5, cos⁡30∘=sin⁡60∘=3/2]\left[\sin 30^\circ = \cos 60^\circ = 0.5,\ \cos 30^\circ = \sin 60^\circ = \sqrt{3}/2\right]

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Answer: (d)

  1. W=pE(cos⁡θ1−cos⁡θ2)W = pE(\cos\theta_1 - \cos\theta_2) with θ1=0\theta_1 = 0, θ2=60∘\theta_2 = 60^\circ.
  2. W=pE(1−0.5)=pE2W = pE(1 - 0.5) = \frac{pE}{2}
  3. So the answer is (d) pE2\frac{pE}{2}.
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