An electric dipole will have minimum potential energy when it subtends an angle bmatrix cos 0° = 1 sin 0° = 0 bmatrix bmatrix cos 90° = 0 cos π = -1 bmatrix (a) π with direction of field. (b) π/2 with direction of field. (c) 3π/2 with direction of field. (d) zero with direction of field.

Answer: (d). U = -pEcos θ is minimum when cos θ = 1. So θ = 0: dipole along the field (stable equilibrium). So the answer is (d) zero with direction of field.

An electric dipole will have minimum potential energy when it… | MHT CET 2024 (11 May, Shift 2)

Q32MHT CET 2024 · 11 MAY · SHIFT 2Easy

Electric Dipole

An electric dipole will have minimum potential energy when it subtends an angle $\begin{bmatrix} \cos 0^\circ = 1 \\ \sin 0^\circ = 0 \end{bmatrix} \begin{bmatrix} \cos 90^\circ = 0 \\ \cos \pi = -1 \end{bmatrix}$

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Answer: (d)

$U = -pE\cos\theta$ is minimum when $\cos\theta = 1$ .
So $\theta = 0$ : dipole along the field (stable equilibrium).
So the answer is (d) zero with direction of field.

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Electric Dipole question from MHT CET 2024 (11 May, Shift 2)

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