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JEE Main 2024 (9 Apr, Shift 2) · Electric Flux & Gauss's Law

Electric Flux & Gauss's Law question from JEE Main 2024 (9 Apr, Shift 2)

Q50JEE Main 2024 · 9 APR · SHIFT 2Medium

Electric Flux & Gauss's Law

An electric field E⃗=(2xi^) NC−1\vec{E} = (2x\hat{i})\text{ NC}^{-1} exists in space. A cube of side 2 m2\text{ m} is placed in the space as per figure given below. The electric flux through the cube is ______ Nm2/C\text{Nm}^{2}/\text{C}.

Figure

Numerical answer type. Work it out, then open the answer.

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Answer: 16

  1. E⃗=2xi^\vec E = 2x\hat i gives flux only through the faces x=2x = 2 m and x=4x = 4 m, each of area 44 m2^2.
  2. Out at x=4x = 4: 8×4=328\times4 = 32. In at x=2x = 2: 4×4=164\times4 = 16.
  3. Net flux =32−16=16= 32 - 16 = 16 N m2^2/C.
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