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JEE Main 2019 (11 Jan, Shift 2) · Electric Dipole

Electric Dipole question from JEE Main 2019 (11 Jan, Shift 2)

Q63JEE Main 2019 · 11 JAN · SHIFT 2Easy

Electric Dipole

An electric field of 1000 V/m is applied to an electric dipole at angle of 45o. The value of electric dipole moment is 10–29 C.m. What is the potential energy of the electric dipole?

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Answer: (a)

$U = -pE\cos\theta$
$U = -10^{-29} \times 1000 \times \frac{1}{\sqrt{2}} \approx -7.07\times10^{-27}$ J
So the answer is (a) $-7 \times 10^{-27}$ J.

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