An electric toaster has resistance of 60 Ω at room temperature (27). The toaster is connected to a 220 V supply. If the current flowing through it reaches 2.75 A, the temperature attained by toaster is around: ( if α = 2 × 10⁻⁴/) (a) 1235 ° C (b) 1667 ° C (c) 694 ° C (d) 1694 ° C

Answer: (d). Hot resistance R = 220/2.75 = 80 Ω. 80 = 60(1 + 2×10⁻⁴ Δ T) ⇒ Δ T = 1/32×10⁻⁴ ≈ 1667° C T = 27 + 1667 = 1694° C. The answer is (d).

An electric toaster has resistance of 60 Ω at room temperature (27)… | JEE Main 2024 (30 Jan, Shift 1)

Q11JEE Main 2024 · 30 JAN · SHIFT 1Medium

Ohm's Law, Resistivity & Temperature

An electric toaster has resistance of $60\ \Omega$ at room temperature $(27^\circ\text{C})$ . The toaster is connected to a $220\text{ V}$ supply. If the current flowing through it reaches $2.75\text{ A}$ , the temperature attained by toaster is around: ( if $\alpha = 2 \times 10^{-4}/^\circ\text{C}$ )

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Answer: (d)

Hot resistance $R = 220/2.75 = 80\ \Omega$ .
$80 = 60(1 + 2\times10^{-4}\,\Delta T) \Rightarrow \Delta T = \dfrac{1/3}{2\times10^{-4}} \approx 1667^\circ$ C
$T = 27 + 1667 = 1694^\circ$ C. The answer is (d).

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