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JEE Main 2026 (2 Apr, Shift 2) · Nature of EM Waves & Wave Equation

Nature of EM Waves & Wave Equation question from JEE Main 2026 (2 Apr, Shift 2)

Q1JEE Main 2026 · 2 APR · SHIFT 2Easy

Nature of EM Waves & Wave Equation

An electromagnetic wave travels in free space along the x-direction. At a particular point in space and time, B⃗=2×10−7j^\vec{B} = 2\times 10^{-7}\hat{j} T is associated with this wave. The value of corresponding electric field E⃗\vec{E} at this point is _______ V/m.

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Answer: (b)

  1. Magnitude: E=cB=3×108×2×10−7=60 V/mE = cB = 3\times 10^{8}\times 2\times 10^{-7} = 60\ \text{V/m}.
  2. Direction: E⃗×B⃗\vec{E}\times\vec{B} must be +i^+\hat{i} with B⃗\vec{B} along j^\hat{j}.
  3. (−k^)×j^=−(k^×j^)=i^(-\hat{k})\times\hat{j} = -(\hat{k}\times\hat{j}) = \hat{i}, so E⃗\vec{E} is along −k^-\hat{k}.
  4. So the answer is (b) −60 k^-60\,\hat{k} V/m.
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