Student Login

Home›Chapters›Dual Nature of Radiation and Matter PYQs›Matter Waves: de Broglie Wavelength›Question 113

JEE Main 2020 (6 Sep, Shift 1) · Matter Waves: de Broglie Wavelength

Matter Waves: de Broglie Wavelength question from JEE Main 2020 (6 Sep, Shift 1)

Q113JEE Main 2020 · 6 SEP · SHIFT 1Easy

Matter Waves: de Broglie Wavelength

An electron, a doubly ionized helium ion (He++) and a proton are having the same kinetic energy. The relation between their respective de-Broglie wavelengths $\lambda$ e, $\lambda$ He++ and $\lambda$ p is:

Show answer and solution

Answer: (c)

He $^{++}$ is an alpha particle. Same kinetic energy: $\lambda \propto \dfrac{1}{\sqrt{m}}$ .
$m_e < m_p < m_{He}$ , so $\lambda_e > \lambda_p > \lambda_{He^{++}}$ .
So the answer is (c).

Report a mistake

More questions on Matter Waves: de Broglie Wavelength

A particle is moving 5 times as fast as an electron. The ratio of the de-Broglie…JEE Main 2020 (2 Sep, Shift 2)
Assuming the nitrogen molecule is moving with r.m.s. velocity at 400 K, the de-Broglie…JEE Main 2020 (6 Sep, Shift 2)
An electron (of mass m) and a photon have the same energy E in the range of a few eV. The…JEE Main 2020 (7 Jan, Shift 2)
An electron (mass m) with initial velocity v = v₀i + v₀j is in an electric field E =…JEE Main 2020 (8 Jan, Shift 2)
An electron of mass m and magnitude of charge |e| initially at rest gets accelerated by a…JEE Main 2020 (9 Jan, Shift 2)
Particle A of mass mA = m/2 moving along the x-axis with velocity v0 collides elastically…JEE Main 2020 (4 Sep, Shift 1)
An electron is accelerated through a potential difference of 10,000 V. Its de Broglie…NEET 2019
A proton and an α -particle are accelerated from rest to the same energy. The de Broglie…NEET 2019