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MHT CET 2021 (20 Sep, Shift 1) · Biot-Savart Law & Circular Coils

Biot-Savart Law & Circular Coils question from MHT CET 2021 (20 Sep, Shift 1)

Q75MHT CET 2021 · 20 SEP · SHIFT 1Easy

Biot-Savart Law & Circular Coils

An electron (e) moves in circular orbit of radius 'r' with uniform speed 'V'. It produces magnetic field 'B' at the centre of circle. The magnetic field B is (μ0=(\mu_0 = permeability of free space)

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Answer: (a)

  1. Equivalent current I=eT=eV2πrI = \frac{e}{T} = \frac{eV}{2\pi r}.
  2. B=μ0I2r=μ0eV4πr2B = \frac{\mu_0 I}{2r} = \frac{\mu_0 eV}{4\pi r^2}
  3. So the answer is (a) μ0e4π(Vr2)\frac{\mu_0 e}{4\pi}\left(\frac{V}{r^2}\right).
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