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NEET 2001 (AIPMT) · Moving Charge in a Magnetic Field

Moving Charge in a Magnetic Field question from NEET 2001 (AIPMT)

Q126NEET 2001 · AIPMTMedium

Moving Charge in a Magnetic Field

An electron having mass m and kinetic energy E enters a uniform magnetic field B perpendicularly, then its frequency will be

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Answer: (c)

  1. Magnetic force gives the centripetal force: evB=mv2r⇒ω=vr=eBmevB = \dfrac{mv^2}{r} \Rightarrow \omega = \dfrac{v}{r} = \dfrac{eB}{m}.
  2. Frequency f=ω2π=eB2πmf = \dfrac{\omega}{2\pi} = \dfrac{eB}{2\pi m}, independent of EE.
  3. So the answer is (c) eB2πm\frac{eB}{2\pi m}.
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