Student Login

Home›Chapters›Atomic Structure PYQs›Transitions, Photon Emission & Excitation›Question 72

NEET 2011 (AIPMT, Mains) · Transitions, Photon Emission & Excitation

Transitions, Photon Emission & Excitation question from NEET 2011 (AIPMT, Mains)

Q72NEET 2011 · AIPMT · MAINSMedium

Transitions, Photon Emission & Excitation

An electron in the hydrogen atom jumps from excited state n to the ground state. The wavelength so emitted illuminates a photosensitive material having work function 2.75 eV. If the stopping potential of the photoelectron is 10 V, then the value of n is

Show answer and solution

Answer: (c)

$K_{max} = eV_0 = 10$ eV, so photon energy $= 2.75 + 10 = 12.75$ eV.
$13.6\left(1 - \frac{1}{n^2}\right) = 12.75 \Rightarrow \frac{1}{n^2} = \frac{1}{16}$
So $n = 4$ , the answer is (c).

Report a mistake

More questions on Transitions, Photon Emission & Excitation

The transition from the state n = 4 to n = 3 in a hydrogen like atom results in…JEE Main 2009 (AIEEE)
The ionization energy of the electron in the hydrogen atom in its ground state is 13.6…NEET 2009 (AIPMT)
Which of the following transitions in hydrogen atoms emit photons of highest frequency?JEE Main 2007 (AIEEE)
Ionization potential of hydrogen atom is 13.6 eV. Hydrogen atoms in the ground state are…NEET 2006 (AIPMT)
Energy E of a hydrogen atom with principal quantum number n is given by E = -13.6n² eV…NEET 2004 (AIPMT)
The wavelengths involved in the spectrum of deuterium (₁²D) are slightly different from…JEE Main 2003 (AIEEE)
Maximum frequency of emission is obtained for the transitionNEET 2000 (AIPMT)
An electron makes a transition from orbit n = 4 to the orbit n = 2 of a hydrogen atom…NEET 1995 (AIPMT)