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NEET 2020 (Phase 1) · Matter Waves: de Broglie Wavelength

Matter Waves: de Broglie Wavelength question from NEET 2020 (Phase 1)

Q112NEET 2020 · PHASE 1Easy

Matter Waves: de Broglie Wavelength

An electron is accelerated from rest through a potential difference of V volt. If the de-Broglie wavelength of the electron is 1.227 $\times$ 10-2 nm, the potential difference is:

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Answer: (c)

$\lambda = \dfrac{1.227}{\sqrt{V}}$ nm $\Rightarrow \sqrt{V} = \dfrac{1.227}{1.227\times10^{-2}} = 100$ .
$V = 10^4$ V.
So the answer is (c) $10^4$ V.

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