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MHT CET 2026 (12 May, Shift 1) · Matter Waves: de Broglie Wavelength

Matter Waves: de Broglie Wavelength question from MHT CET 2026 (12 May, Shift 1)

Q22MHT CET 2026 · 12 MAY · SHIFT 1Medium

Matter Waves: de Broglie Wavelength

An electron is moving with initial velocity v⃗=ak^\vec{v} = a\hat{k} in a magnetic field B⃗=bj^\vec{B} = b\hat{j}. Its de-Broglie wavelength will

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Answer: (d)

  1. v⃗\vec v along k^\hat k and B⃗\vec B along j^\hat j: magnetic force F⃗=−e(v⃗×B⃗)\vec F = -e(\vec v\times\vec B) is always perpendicular to v⃗\vec v.
  2. It does no work, so speed and ∣p∣|p| stay constant.
  3. λ=h/p\lambda = h/p stays constant.
  4. So the answer is (d) remain constant.
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