Physics Circle home Student Login

Home›Chapters›Dual Nature of Radiation and Matter PYQs›Matter Waves: de Broglie Wavelength›Question 23

MHT CET 2026 (20 Apr, Shift 2) · Matter Waves: de Broglie Wavelength

Matter Waves: de Broglie Wavelength question from MHT CET 2026 (20 Apr, Shift 2)

Q23MHT CET 2026 · 20 APR · SHIFT 2Medium

Matter Waves: de Broglie Wavelength

An electron is moving with initial velocity v⃗=V0j^\vec{v} = V_0\hat{j} in a magnetic field B⃗=B0i^\vec{B} = B_0\hat{i}. Its de-Broglie wavelength will

Show answer and solution

Answer: (c)

  1. Magnetic force is always perpendicular to velocity, so it does no work.
  2. Speed, hence momentum magnitude p=mvp = mv, is constant.
  3. λ=h/(mv)\lambda = h/(mv) is constant.
  4. So the answer is (c) remains constant.
Report a mistake

More questions on Matter Waves: de Broglie Wavelength