Physics Circle home Student Login

Home›Chapters›Atomic Structure PYQs›Bohr Model: Orbits, Speed & Angular Momentum›Question 25

MHT CET 2026 (13 Apr, Shift 1) · Bohr Model: Orbits, Speed & Angular Momentum

Bohr Model: Orbits, Speed & Angular Momentum question from MHT CET 2026 (13 Apr, Shift 1)

Q25MHT CET 2026 · 13 APR · SHIFT 1Medium

Bohr Model: Orbits, Speed & Angular Momentum

An electron is revolving in a circular orbit of radius 'r' in hydrogen atom. Using Bohr's theory, the angular momentum of the electron is

(M = magnetic dipole moment, m = mass of electron)

Show answer and solution

Answer: (c)

  1. M=IA=ev2πr⋅πr2=evr2M = IA = \frac{ev}{2\pi r}\cdot\pi r^2 = \frac{evr}{2}
  2. L=mvr⇒M=e2mLL = mvr \Rightarrow M = \frac{e}{2m}L
  3. L=2mMeL = \frac{2mM}{e}, so the answer is (c).
Report a mistake

More questions on Bohr Model: Orbits, Speed & Angular Momentum