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MHT CET 2023 (12 May, Shift 2) · Biot-Savart Law & Circular Coils

Biot-Savart Law & Circular Coils question from MHT CET 2023 (12 May, Shift 2)

Q57MHT CET 2023 · 12 MAY · SHIFT 2Medium

Biot-Savart Law & Circular Coils

An electron makes a full rotation in a circle of radius 0.8 m0.8\text{ m} in one second. The magnetic field at the centre of the circle is (μ0=4π×10−7(\mu_0 = 4\pi \times 10^{-7} SI units)

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Answer: (a)

  1. I=ef=1.6×10−19 AI = ef = 1.6 \times 10^{-19}\text{ A} (one rotation per second).
  2. B=μ0I2r=4π×10−7×1.6×10−191.6=4π×10−26 TB = \frac{\mu_0 I}{2r} = \frac{4\pi \times 10^{-7} \times 1.6 \times 10^{-19}}{1.6} = 4\pi \times 10^{-26}\text{ T}
  3. So the answer is (a) 4π×10−26 T4\pi \times 10^{-26}\text{ T}.
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