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NEET 1995 (AIPMT) · Transitions, Photon Emission & Excitation

Transitions, Photon Emission & Excitation question from NEET 1995 (AIPMT)

Q80NEET 1995 · AIPMTEasy

Transitions, Photon Emission & Excitation

An electron makes a transition from orbit n=4n = 4 to the orbit n=2n = 2 of a hydrogen atom. What is the wavelength of the emitted radiations? (RR = Rydberg's constant)

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Answer: (d)

  1. 1λ=R(122−142)=R(4−116)=3R16\frac{1}{\lambda} = R\left(\frac{1}{2^2}-\frac{1}{4^2}\right) = R\left(\frac{4-1}{16}\right) = \frac{3R}{16}
  2. λ=163R\lambda = \frac{16}{3R}
  3. So the answer is (d) 163R\frac{16}{3R}.
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