An electron of a hydrogen like atom, having Z = 4, jumps from 4 th… | JEE Main 2023 (1 Feb, Shift 2)

Q33JEE Main 2023 · 1 FEB · SHIFT 2Medium

Transitions, Photon Emission & Excitation

An electron of a hydrogen like atom, having $Z = 4$ , jumps from $4$ th energy state to $2$ nd energy state. The energy released in this process, will be:

(Given Rch = $13.6\text{ eV}$ )

Where R = Rydberg constant

c = Speed of light in vacuum

h = Planck's constant

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Answer: (b)

$\Delta E = Rhc\, Z^2 \left(\frac{1}{n_f^2} - \frac{1}{n_i^2}\right)$
$\Delta E = 13.6 \times 16 \times \left(\frac{1}{4} - \frac{1}{16}\right) = 13.6 \times 16 \times \frac{3}{16}$
$\Delta E = 40.8$ eV, so the answer is (b).

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Transitions, Photon Emission & Excitation question from JEE Main 2023 (1 Feb, Shift 2)

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