Physics Circle home Student Login

Home›Chapters›Atomic Structure PYQs›Transitions, Photon Emission & Excitation›Question 70

NEET 2012 (AIPMT, Prelims) · Transitions, Photon Emission & Excitation

Transitions, Photon Emission & Excitation question from NEET 2012 (AIPMT, Prelims)

Q70NEET 2012 · AIPMT · PRELIMSMedium

Transitions, Photon Emission & Excitation

An electron of a stationary hydrogen atom passes from the fifth energy level to the ground level. The velocity that the atom acquired as a result of photon emission will be

Show answer and solution

Answer: (a)

  1. Momentum conservation: mv=hλmv = \frac{h}{\lambda} (mm = mass of the atom).
  2. 1λ=R(1−125)=24R25\frac{1}{\lambda} = R\left(1 - \frac{1}{25}\right) = \frac{24R}{25}
  3. v=24hR25mv = \frac{24hR}{25m}
  4. So the answer is (a).
Report a mistake

More questions on Transitions, Photon Emission & Excitation