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JEE Main 2024 (30 Jan, Shift 1) · Transitions, Photon Emission & Excitation

Transitions, Photon Emission & Excitation question from JEE Main 2024 (30 Jan, Shift 1)

Q21JEE Main 2024 · 30 JAN · SHIFT 1Medium

Transitions, Photon Emission & Excitation

An electron of hydrogen atom in an excited state is having energy En=−0.85 eVE_n = -0.85\text{ eV}. The maximum number of allowed transitions to lower energy level is _________.

Numerical answer type. Work it out, then open the answer.

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Answer: 6

  1. En=−13.6n2=−0.85E_n = -\frac{13.6}{n^2} = -0.85 eV ⇒n2=16\Rightarrow n^2 = 16, n=4n = 4.
  2. Maximum number of transitions =n(n−1)2=4×32= \frac{n(n-1)}{2} = \frac{4 \times 3}{2}
  3. So the answer is 6.
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