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MHT CET 2021 (23 Sep, Shift 1) · Matter Waves: de Broglie Wavelength

Matter Waves: de Broglie Wavelength question from MHT CET 2021 (23 Sep, Shift 1)

Q103MHT CET 2021 · 23 SEP · SHIFT 1Medium

Matter Waves: de Broglie Wavelength

An electron of mass ' $m$ ' and a photon have same energy ' $E$ '. The ratio of de-Broglie wavelength of electron to the wavelength of photon is $(c =$ velocity of light)

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Answer: (c)

$\lambda_e = \dfrac{h}{\sqrt{2mE}}$ , $\lambda_{ph} = \dfrac{hc}{E}$ .
$\dfrac{\lambda_e}{\lambda_{ph}} = \dfrac{E}{c\sqrt{2mE}} = \dfrac{1}{c}\sqrt{\dfrac{E}{2m}}$
So the answer is (c).

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