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NEET 2016 (Phase 1) · Matter Waves: de Broglie Wavelength

Matter Waves: de Broglie Wavelength question from NEET 2016 (Phase 1)

Q133NEET 2016 · PHASE 1Medium

Matter Waves: de Broglie Wavelength

An electron of mass m and a photon have same energy E. The ratio of de-Broglie wavelengths associated with them is

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Answer: (c)

Electron: $\lambda_e = \dfrac{h}{\sqrt{2mE}}$ . Photon: $\lambda_{ph} = \dfrac{hc}{E}$ .
$\dfrac{\lambda_e}{\lambda_{ph}} = \dfrac{E}{c\sqrt{2mE}} = \dfrac{1}{c}\left(\dfrac{E}{2m}\right)^{1/2}$
So the answer is (c).

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