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NEET 1996 (AIPMT) · Cathode Rays, Thomson's Experiment & Gas Discharge

Cathode Rays, Thomson's Experiment & Gas Discharge question from NEET 1996 (AIPMT)

Q10NEET 1996 · AIPMTEasy

Cathode Rays, Thomson's Experiment & Gas Discharge

An electron of mass $m$ and charge $e$ is accelerated from rest through a potential difference $V$ in vacuum. Its final velocity will be

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Answer: (a)

Work done by the field becomes kinetic energy: $eV = \frac{1}{2}mv^2$ .
$v = \sqrt{\frac{2eV}{m}}$
So the answer is (a).

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