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MHT CET 2024 (4 May, Shift 2) · Motion of Charges in an Electric Field

Motion of Charges in an Electric Field question from MHT CET 2024 (4 May, Shift 2)

Q8MHT CET 2024 · 4 MAY · SHIFT 2Easy

Motion of Charges in an Electric Field

An electron of mass ' $m$ ' and charge ' $q$ ' is accelerated from rest in a uniform electric field of intensity ' $E$ '. The velocity acquired by it as it travels a distance ' $l$ ' is ' $v$ '. The ratio $\frac{q}{m}$ in terms of $E, l$ and $v$ is

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Answer: (a)

$a = \frac{qE}{m}$ ; from rest, $v^2 = 2al = \frac{2qEl}{m}$ .
$\frac{q}{m} = \frac{v^2}{2El}$
So the answer is (a).

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