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JEE Main 2021 (22 Jul, Shift 2) · Matter Waves: de Broglie Wavelength

Matter Waves: de Broglie Wavelength question from JEE Main 2021 (22 Jul, Shift 2)

Q94JEE Main 2021 · 22 JUL · SHIFT 2Easy

Matter Waves: de Broglie Wavelength

An electron of mass me and a proton of mass mp are accelerated through the same potential difference. The ratio of the de-Broglie wavelength associated with the electron to that with the proton is

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Answer: (d)

$\lambda = \dfrac{h}{\sqrt{2meV}}$ ; both have charge $e$ and the same $V$ , so $\lambda \propto \dfrac{1}{\sqrt{m}}$ .
$\dfrac{\lambda_e}{\lambda_p} = \sqrt{\dfrac{m_p}{m_e}}$
So the answer is (d).

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