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JEE Main 2021 (25 Feb, Shift 2) · Matter Waves: de Broglie Wavelength

Matter Waves: de Broglie Wavelength question from JEE Main 2021 (25 Feb, Shift 2)

Q96JEE Main 2021 · 25 FEB · SHIFT 2Easy

Matter Waves: de Broglie Wavelength

An electron of mass me and a proton of mass mp = 1836 me are moving with the same speed. The ratio of their de Broglie wavelength $\frac{\lambda_{electron}}{\lambda_{proton}}$ will be:

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Answer: (b)

$\lambda = \dfrac{h}{mv}$ ; same speed gives $\lambda \propto \dfrac{1}{m}$ .
$\dfrac{\lambda_e}{\lambda_p} = \dfrac{m_p}{m_e} = 1836$
So the answer is (b) 1836.

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