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JEE Main 2022 (26 Jun, Shift 1) · Matter Waves: de Broglie Wavelength

Matter Waves: de Broglie Wavelength question from JEE Main 2022 (26 Jun, Shift 1)

Q87JEE Main 2022 · 26 JUN · SHIFT 1Medium

Matter Waves: de Broglie Wavelength

An electron with speed v and a photon with speed c have the same de-Broglie wavelength. If the kinetic energy and momentum of electron are Ee and pe and that of photon are Eph and pph respectively. Which of the following is correct?

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Answer: (b)

  1. Same λ\lambda means same momentum: pe=pph=pp_e = p_{ph} = p, so (c) and (d) are wrong.
  2. Electron: Ee=12mv2=12pvE_e = \frac{1}{2}mv^2 = \frac{1}{2}pv. Photon: Eph=pcE_{ph} = pc.
  3. EeEph=v2c\dfrac{E_e}{E_{ph}} = \dfrac{v}{2c}
  4. So the answer is (b).
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