An element A decays into element C by a two step process A → B + ₂He⁴; B → C + 2e⁻ Then (a) A and C are isotopes (b) A and C are isobars (c) A and B are isotopes (d) A and B are isobars

Answer: (a). α emission: B has (A-4, Z-2). Two β⁻: C has (A-4, Z). A and C have the same atomic number, different mass number, so they are isotopes. So the answer is (a) A and C are isotopes.

An element A decays into element C by a two step process A → B +… | NEET 1989 (AIPMT)

Q48NEET 1989 · AIPMTEasy

Radioactive Decays: Alpha, Beta, Gamma

An element $A$ decays into element $C$ by a two step process

$A \rightarrow B + {}_{2}\text{He}^{4};\ B \rightarrow C + 2e^{-}$

Then

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Answer: (a)

$\alpha$ emission: B has $(A-4,\ Z-2)$ .
Two $\beta^-$ : C has $(A-4,\ Z)$ .
A and C have the same atomic number, different mass number, so they are isotopes.
So the answer is (a) $A$ and $C$ are isotopes.

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