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JEE Main 2020 (7 Jan, Shift 2) · Power

Power question from JEE Main 2020 (7 Jan, Shift 2)

Q31JEE Main 2020 · 7 JAN · SHIFT 2Medium

Power

An elevator in a building can carry a maximum of 10 persons, with the average mass of each person being 68 kg. The mass of the elevator itself is 920 kg and it moves with a constant speed of 3 m/s. The frictional force opposing the motion is 6000 N. If the elevator is moving up with its full capacity, the power delivered by the motor to the elevator (g = 10 m/s2) must be at least:

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Answer: (d)

  1. Total mass =10×68+920=1600 kg= 10 \times 68 + 920 = 1600\text{ kg}.
  2. At constant speed F=mg+f=16000+6000=22000 NF = mg + f = 16000 + 6000 = 22000\text{ N}.
  3. P=Fv=22000×3=66000 WP = Fv = 22000 \times 3 = 66000\text{ W}
  4. So the answer is (d) 66000 W.
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