An emf of 0.08 V is induced in a metal rod of length 10 cm held normal to a uniform magnetic field of 0.4 T, when moves with a velocity of: (a) 20 ms⁻¹ (b) 2 ms⁻¹ (c) 3.2 ms⁻¹ (d) 0.5 ms⁻¹

Answer: (b). ε = Blv ⇒ v = (ε)/(Bl) v = (0.08)/(0.4 × 0.1) = 2 m/s So the answer is (b) 2 m s ⁻¹.

An emf of 0.08 V is induced in a metal rod of length 10 cm held… | JEE Main 2023 (8 Apr, Shift 2)

Q24JEE Main 2023 · 8 APR · SHIFT 2Easy

Motional EMF

An emf of $0.08\text{ V}$ is induced in a metal rod of length $10\text{ cm}$ held normal to a uniform magnetic field of $0.4\text{ T}$ , when moves with a velocity of:

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Answer: (b)

$\varepsilon = Blv \Rightarrow v = \frac{\varepsilon}{Bl}$
$v = \frac{0.08}{0.4 \times 0.1} = 2$ m/s
So the answer is (b) $2$ m s $^{-1}$ .

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