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NEET 2007 (AIPMT) · Heat Engines, Refrigerators & Second Law

Heat Engines, Refrigerators & Second Law question from NEET 2007 (AIPMT)

Q79NEET 2007 · AIPMTMedium

Heat Engines, Refrigerators & Second Law

An engine has an efficiency of 1/6. When the temperature of sink is reduced by 62oC, its efficiency is doubled. Temperatures of the source is

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Answer: (c)

  1. η=1−T2T1\eta = 1 - \frac{T_2}{T_1}: T2=56T1T_2 = \frac{5}{6}T_1; after reduction η=13\eta = \frac{1}{3}, so T2−62=23T1T_2 - 62 = \frac{2}{3}T_1.
  2. A change of 62∘C62^\circ\text{C} equals 62 K. Subtract: T16=62⇒T1=372 K\frac{T_1}{6} = 62 \Rightarrow T_1 = 372\text{ K}.
  3. T1=372−273=99∘CT_1 = 372 - 273 = 99^\circ\text{C}
  4. So the answer is (c) 99∘C99^\circ\text{C}.
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