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MHT CET 2026 (15 Apr, Shift 1) · Combination of Lenses

Combination of Lenses question from MHT CET 2026 (15 Apr, Shift 1)

Q2MHT CET 2026 · 15 APR · SHIFT 1Easy

Combination of Lenses

An equiconvex lens of focal length F is cut in to two equal parts along the vertical axis. The focal length of each part will be

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Answer: (c)

  1. Cutting perpendicular to the principal axis gives two plano-convex halves (one curved face each).
  2. Equiconvex: 1F=(μ−1)2R\frac{1}{F} = (\mu-1)\frac{2}{R}; each half: 1F′=(μ−1)1R=12F\frac{1}{F'} = (\mu-1)\frac{1}{R} = \frac{1}{2F}.
  3. F′=2FF' = 2F
  4. So the answer is (c) 2F2F.
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