An experiment takes 10 minutes to raise the temperature of water in a… | JEE Main 2015 (11 Apr, Shift 1)

Q47JEE Main 2015 · 11 APR · SHIFT 1Medium

Calorimetry, Latent Heat & Mechanical Equivalent of Heat

An experiment takes 10 minutes to raise the temperature of water in a container from 0oC to 100oC and another 55 minutes to convert it totally into steam by a heater supplying heat at a uniform rate. Neglecting the specific heat of the container and taking specific heat of water to be 1 cal/goC, the heat of vapourization according to this experiment will come out to be:

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Answer: (c)

Heat rate $= \dfrac{m \times 1 \times 100}{10} = 10m\text{ cal/min}$
In 55 min: $mL = 55 \times 10m \Rightarrow L = 550\text{ cal/g}$
So the answer is (c) $550\text{ cal/g}$ .

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