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MHT CET 2021 (22 Sep, Shift 2) · Thermodynamic Processes

Thermodynamic Processes question from MHT CET 2021 (22 Sep, Shift 2)

Q185MHT CET 2021 · 22 SEP · SHIFT 2Medium

Thermodynamic Processes

An ideal gas at 27∘C27^\circ\text{C} is compressed adiabatically to (8/27)(8/27) of its original volume. If ratio of specific heats, γ=5/3\gamma = 5/3 then the rise in temperature of the gas is

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Answer: (d)

  1. Adiabatic: T2=T1(V1V2)γ−1T_2 = T_1\left(\frac{V_1}{V_2}\right)^{\gamma-1}, T1=300 KT_1 = 300\ \text{K}.
  2. T2=300(278)2/3=300×94=675 KT_2 = 300\left(\frac{27}{8}\right)^{2/3} = 300 \times \frac{9}{4} = 675\ \text{K}
  3. Rise =675−300=375 K= 675 - 300 = 375\ \text{K}
  4. So the answer is (d) 375 K.
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