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NEET 2022 (Phase 2) · Thermodynamic Processes

Thermodynamic Processes question from NEET 2022 (Phase 2)

Q170NEET 2022 · PHASE 2Medium

Thermodynamic Processes

An ideal gas follows a process described by the equation PV2=CPV^{2} = C from the initial (P1,V1,T1)(P_1, V_1, T_1) to final (P2,V2,T2)(P_2, V_2, T_2) thermodynamic states, where C is a constant. Then

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Answer: (d)

  1. PV2=CPV^2 = C and PV=nRTPV = nRT give T=PVnR=CnRVT = \frac{PV}{nR} = \frac{C}{nRV}, so T∝1VT \propto \frac{1}{V}.
  2. Also P∝1V2P \propto \frac{1}{V^2}: if P1>P2P_1 > P_2 then V1<V2V_1 < V_2, so (a) is false, and then T1>T2T_1 > T_2, so (b) is false.
  3. If V2>V1V_2 > V_1 then T2<T1T_2 < T_1, so (c) is false and (d) is true.
  4. So the answer is (d).
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