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MHT CET 2021 (22 Sep, Shift 2) · Molecular Speeds & Maxwell Distribution

Molecular Speeds & Maxwell Distribution question from MHT CET 2021 (22 Sep, Shift 2)

Q62MHT CET 2021 · 22 SEP · SHIFT 2Easy

Molecular Speeds & Maxwell Distribution

An ideal gas having molar mass 'M0M_0', has r.m.s. velocity 'V' at temperature 'T'. Then

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Answer: (b)

  1. V=3RTM0⇒V2=3RM0TV = \sqrt{\frac{3RT}{M_0}} \Rightarrow V^2 = \frac{3R}{M_0}T
  2. With M0M_0 fixed, V2T=3RM0\frac{V^2}{T} = \frac{3R}{M_0} is constant.
  3. So the answer is (b).
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