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MHT CET 2026 (20 Apr, Shift 2) · Thermodynamic Processes

Thermodynamic Processes question from MHT CET 2026 (20 Apr, Shift 2)

Q40MHT CET 2026 · 20 APR · SHIFT 2Medium

Thermodynamic Processes

An ideal gas having pressure PP, volume VV and temperature TT is expanded isothermally, to a volume 3V3V and final pressure PIP_I. The same gas is expanded adiabatically to a volume 3V3V, the final pressure being PAP_A. The ratio PAPI\frac{P_A}{P_I} is (CPCV=γ)\left(\frac{C_P}{C_V} = \gamma\right)

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Answer: (c)

  1. Isothermal: PI(3V)=PV⇒PI=P3P_I(3V) = PV \Rightarrow P_I = \frac{P}{3}.
  2. Adiabatic: PA(3V)γ=PVγ⇒PA=P3γP_A(3V)^{\gamma} = PV^{\gamma} \Rightarrow P_A = \frac{P}{3^{\gamma}}.
  3. PAPI=33γ=31−γ\frac{P_A}{P_I} = \frac{3}{3^{\gamma}} = 3^{1-\gamma}
  4. So the answer is (c) 3(1−γ)3^{(1-\gamma)}.
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