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MHT CET 2026 (12 May, Shift 2) · Heat Engines, Refrigerators & Second Law

Heat Engines, Refrigerators & Second Law question from MHT CET 2026 (12 May, Shift 2)

Q2MHT CET 2026 · 12 MAY · SHIFT 2Easy

Heat Engines, Refrigerators & Second Law

An ideal gas heat engine operate in Carnot cycle between 327∘C327^\circ\text{C} and 227∘C227^\circ\text{C}. It absorbs 6×1046 \times 10^{4} cal of heat at higher temperature. How much is the amount of heat converted in to work?

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Answer: (b)

  1. T1=600T_1 = 600 K, T2=500T_2 = 500 K, so η=1−500600=16\eta = 1 - \frac{500}{600} = \frac{1}{6}
  2. W=ηQ1=16×6×104=1×104W = \eta Q_1 = \frac{1}{6} \times 6 \times 10^4 = 1 \times 10^4 cal
  3. So the answer is (b) 1×1041 \times 10^4 cal.
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