Physics Circle home Student Login

Home›Chapters›Thermodynamics PYQs›Heat Engines, Refrigerators & Second Law›Question 86

NEET 2003 (AIPMT) · Heat Engines, Refrigerators & Second Law

Heat Engines, Refrigerators & Second Law question from NEET 2003 (AIPMT)

Q86NEET 2003 · AIPMTEasy

Heat Engines, Refrigerators & Second Law

An ideal gas heat engine operates in a Carnot cycle between 227oC and 127oC. It absorbs 6 kcal at the higher temperature. The amount of heat (in kcal) converted into work is equal to

Show answer and solution

Answer: (d)

  1. T1=500T_1 = 500 K, T2=400T_2 = 400 K, so η=1−400500=0.2\eta = 1 - \frac{400}{500} = 0.2
  2. W=0.2×6=1.2W = 0.2 \times 6 = 1.2 kcal
  3. So the answer is (d) 1.2.
Report a mistake

More questions on Heat Engines, Refrigerators & Second Law