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NEET 2005 (AIPMT) · Heat Engines, Refrigerators & Second Law

Heat Engines, Refrigerators & Second Law question from NEET 2005 (AIPMT)

Q82NEET 2005 · AIPMTEasy

Heat Engines, Refrigerators & Second Law

An ideal gas heat engine operates in Carnot cycle between 227oC and 127oC. It absorbs 6 ×\times 104 cal of heat at higher temperature. Amount of heat converted to work is

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Answer: (d)

  1. T1=500T_1 = 500 K, T2=400T_2 = 400 K, so η=1−400500=0.2\eta = 1 - \frac{400}{500} = 0.2
  2. W=0.2×6×104=1.2×104W = 0.2 \times 6 \times 10^4 = 1.2 \times 10^4 cal
  3. So the answer is (d) 1.2×1041.2 \times 10^4 cal.
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