An ideal gas occupies a volume of 2m3 at a pressure of 3 × 106 Pa. The energy of the gas is: (a) 6 × 104 J (b) 9 × 106 J (c) 3 × 102 J (d) 108 J

Answer: (b). Taking the gas as monatomic, internal energy U = 3/2nRT = 3/2PV. U = 3/2 × 3 × 10⁶ × 2 = 9 × 10⁶ J. So the answer is (b) 9 × 10⁶ J.

An ideal gas occupies a volume of 2m3 at a pressure of 3 × 106 Pa… | JEE Main 2019 (12 Jan, Shift 1)

Q70JEE Main 2019 · 12 JAN · SHIFT 1Medium

Gas Laws & Ideal Gas Equation

An ideal gas occupies a volume of 2m3 at a pressure of 3 $\times$ 106 Pa. The energy of the gas is:

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Answer: (b)

Taking the gas as monatomic, internal energy $U = \frac{3}{2}nRT = \frac{3}{2}PV$ .
$U = \frac{3}{2} \times 3 \times 10^6 \times 2 = 9 \times 10^6\text{ J}$ .
So the answer is (b) $9 \times 10^6$ J.