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MHT CET 2025 (21 Apr, Shift 2) · RL and RC Series Circuits

RL and RC Series Circuits question from MHT CET 2025 (21 Apr, Shift 2)

Q14MHT CET 2025 · 21 APR · SHIFT 2Easy

RL and RC Series Circuits

An ideal inductor of (1π)H\left(\frac{1}{\pi}\right)\text{H} is connected in series with a 300 Ω300\ \Omega resistor. If a 20 V, 200 Hz20\text{ V},\ 200\text{ Hz} alternating source is connected across the combination, the phase difference between the voltage and current is

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Answer: (b)

  1. XL=2πfL=2π×200×1π=400 ΩX_L = 2\pi f L = 2\pi \times 200 \times \frac{1}{\pi} = 400\ \Omega
  2. tan⁡ϕ=XLR=400300=43\tan\phi = \frac{X_L}{R} = \frac{400}{300} = \frac{4}{3}
  3. So the answer is (b) tan⁡−1(43)\tan^{-1}\left(\frac{4}{3}\right).
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