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JEE Main 2023 (6 Apr, Shift 1) · AC Generator & Transformer

AC Generator & Transformer question from JEE Main 2023 (6 Apr, Shift 1)

Q33JEE Main 2023 · 6 APR · SHIFT 1Difficult

AC Generator & Transformer

An ideal transformer with purely resistive load operates at 12 kV12\text{ kV} on the primary side. It supplies electrical energy to a number of nearby houses at 120 V120\text{ V}. The average rate of energy consumption in the houses served by the transformer is 60 kW\text{kW}. The value of resistive load (Rs)(\text{Rs}) required in the secondary circuit will be ___________ mΩ\text{m}\Omega.

Numerical answer type. Work it out, then open the answer.

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Answer: 240

  1. Secondary load: P=Vs2RsP = \dfrac{V_s^2}{R_s}.
  2. Rs=120260000=1440060000=0.24 ΩR_s = \dfrac{120^2}{60000} = \dfrac{14400}{60000} = 0.24\ \Omega
  3. Rs=240 mΩR_s = 240\text{ m}\Omega
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