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MHT CET 2025 (20 Apr, Shift 1) · Rolling Motion

Rolling Motion question from MHT CET 2025 (20 Apr, Shift 1)

Q13MHT CET 2025 · 20 APR · SHIFT 1Easy

Rolling Motion

An inclined plane makes an angle $30^\circ$ with the horizontal. A solid sphere rolling down an inclined plane from rest without slipping has linear acceleration ( $g =$ acceleration due gravity) ( $\sin 30^\circ = 0.5$ )

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Answer: (b)

Rolling down an incline: $a = \frac{g\sin\theta}{1 + k^2/R^2}$ .
Solid sphere: $a = \frac{g\sin\theta}{7/5} = \frac{5}{7}g\times 0.5$
$a = \frac{5g}{14}$
So the answer is (b) $\frac{5g}{14}$ .

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