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MHT CET 2024 (3 May, Shift 1) · RL and RC Series Circuits

RL and RC Series Circuits question from MHT CET 2024 (3 May, Shift 1)

Q24MHT CET 2024 · 3 MAY · SHIFT 1Medium

RL and RC Series Circuits

An inductance coil has a resistance of 80 Ω80\ \Omega. When on AC signal of frequency 480 Hz is applied to the coil, the voltage leads the current by 45∘45^\circ. The inductance of the coil in henry is

[sin⁡45∘=cos⁡45∘=1/2]\left[\sin 45^\circ = \cos 45^\circ = 1/\sqrt{2}\right]

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Answer: (d)

  1. ϕ=45∘⇒XL=R=80 Ω\phi = 45^\circ \Rightarrow X_L = R = 80\ \Omega.
  2. 2πfL=80⇒L=802π×480=112π H2\pi f L = 80 \Rightarrow L = \frac{80}{2\pi \times 480} = \frac{1}{12\pi}\text{ H}
  3. So the answer is (d) 112π\frac{1}{12\pi} H.
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